Sunday, March 25, 2012

AXIAL LOADING; NORMAL STRESS BASICS AND TUTORIALS

AXIAL LOADING; NORMAL STRESS TUTORIALS
What Is Axial Loading? What Is Stress?

The deformation caused in a body by external forces or other actions generally varies from one point to another, i.e., it is not homogeneous. In fact, a homogeneous deformation is rare. It occurs, for example, in a body with isostatic supports under a uniform temperature variation or in a slender member under constant axial force.



Rod BC of the example considered in the preceding section is a two-force member and, therefore, the forces FBC and F'BC acting on its ends B and C (Fig. 1.5) are directed along the axis of the rod. We say that the rod is under axial loading.

An actual example of structural members under axial loading is provided by the members of the bridge truss shown in Photo 1.1.



Returning to rod BC of Fig. 1.5, we recall that the section we passed through the rod to determine the internal force in the rod and the corresponding stress was perpendicular to the axis of the rod; the internal force was therefore normal to the plane of the section (Fig. 1.7) and the corresponding stress is described as a normal stress.


Thus, formula (1.5) gives us the normal stress in a member under axial loading:


σ =P/A 

We should also note that, in formula (1.5), s is obtained by dividing the magnitude P of the resultant of the internal forces distributed over the cross section by the area A of the cross section; it represents, therefore, the average value of the stress over the cross section, rather than the stress at a specific point of the cross section.

To define the stress at a given point Q of the cross section, we should consider a small area DA. Dividing the magnitude of DF by DA, we obtain the average value of the stress over DA. Letting DA approach zero, we obtain the stress at point Q:

σ = lim dF/dA      as dA approaches infinity (1.6)

In general, the value obtained for the stress s at a given point Q of the section is different from the value of the average stress given by formula (1.5), and s is found to vary across the section. In a slender rod subjected to equal and opposite concentrated loads P and P' , this variation is small in a section away from the points of application of the concentrated loads, but it is quite noticeable in the neighborhood of these 

It follows from Eq. (1.6) that the magnitude of the resultant of the distributed internal forces is

∫dF = ∫σ dA     lower limit = A

But the conditions of equilibrium of each of the portions of rod require that this magnitude be equal to the magnitude P of the concentrated loads. We have, therefore,
P = ∫dF = ∫σ dA    lower limit = A

which means that the volume under each of the stress surfaces must be equal to the magnitude P of the loads. This, however, is the only information that we can derive from our knowledge of statics, regarding the distribution of normal stresses in the various sections of the rod. 

The actual distribution of stresses in any given section is statically indeterminate. To learn more about this distribution, it is necessary to consider the deformations resulting from the particular mode of application of the loads at the ends of the rod.

In practice, it will be assumed that the distribution of normal stresses in an axially loaded member is uniform, except in the immediate vicinity of the points of application of the loads. The value s of the stress is then equal to save and can be obtained from formula (1.5). 

However, we should realize that, when we assume a uniform distribution of stresses in the section, i.e., when we assume that the internal forces are uniformly distributed across the section, it follows from elementary statics† that the resultant P of the internal forces must be applied at the centroid C of the section. 

This means that a uniform distribution of stress is possible only if the line of action of the concentrated loads P and P' passes through the centroid of the section considered. This type of loading is called centric loading and will be assumed to take place in all straight two-force members found in trusses and pin-connected structures, such as the one considered in Fig. 1.1. 

However, if a two-force member is loaded axially, but eccentrically we find from the conditions of equilibrium of the portion of member that the internal forces in a given section must be equivalent to a force P applied at the centroid of the section and a couple M of moment M = Pd. The distribution of forces—and, thus, the corresponding distribution of stresses—cannot be uniform. Nor can the distribution of stresses be symmetric.

DRILLING A TILE WITHOUT CRACKING IT BASIC AND TUTORIALS

TILE DRILLING WITHOUT CRACKING THE TILE TECHNIQUES
How To Drill Tiles Without Cracking It?

This article is a step by step process in drilling tiles, without cracking it. Many installations in kitchens involve drilling through a tiled surface.

It is essential to use the correct technique for drilling through tiles so they do not crack. The dust created from drilling ceramic tiles can discolor grout and sealant so you may want to vacuum dust from holes as you drill them.


Tools and materials
Felt-tip pen
masking tape
drill and bits,
vacuum cleaner
wall plug

Steps


1. Mark the point for the hole using a felt-tip pen. Apply some masking tape over the mark—it should still be visible.


2. Fit a tile drill bit. Remember to switch off any hammer action.



Selecting a tile bit: Tile bits differ in shape based on material. The spear-shaped tip penetrates a tile, then enlarges the hole to the diameter of the tip’s base.

Caution: Take care when changing a bit after operating a drill: the bit may be hot. Wear gloves to avoid a burn.


3.  Position a vacuum cleaner below the mark and switch it on. Start up the drill on a low speed, and slowly increase the speed.


4. Once through the tile, change the bit for a masonry bit or wood bit, depending on the surface below. Drill to the required depth.





5. Remove the masking tape from the tile, then plug the hole with the appropriate wall plug, and insert the fastener as required.



Selecting wall plugs

Unless you are using masonry screws, a wall plug is required to secure a screw that is
inserted into masonry. The plugs shown here are masonry plugs, and the different colors relate to their width, or gauge.

Wall plugs are also needed to make strong connections in hollow walls such as stud walls; these are of a different design from those used in masonry.



CONSTRUCTION MANAGEMENT - Case study: Stoke-on-Trent Schools, UK

In 1997 many of the schools in Stoke-on-Trent were in a dilapidated state and not fit for modern teaching and learning practice. The school...